Estimate the value of the equilibrium constant
for the reaction below from the data in the graph.
2NO(g) +02(8) = 2NO2(g)
1.000
0.800
0.600
NO2
Concentration (mm)
0.400
NO
0.200
0.00
0
2000
4000
6000
8000

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

C. 1s22s22p63s23p43d104s24p5

Sorry i dont understand the question can you rephase it?