Find the pH, pOH, and [H+] for a solution with a [OH-] of 10^-9 M. Is the solution acidic or basic?

pOH = 9; pH = 5; Solution is acidic

Explanation:

the -log[OH] = the pOH. this means the pOH is 9.

the pOH and the pH add up to 14. 14-9=5 so the pH is 5.

the solution is acidic because the pOH is greater then the pH.

The answer to your question is  pOH = 9, pH = 5, [H⁺] = 1 x 10⁻⁵ M, it is an acid.

Explanation:

Data

[OH⁻] = 10⁻⁹ M

pH = ?

pOH = ?

[H⁺] = ?

Process

1.- Calculate the pOH

pOH = -log [OH]

-Substitution

pOH = -log [10⁻⁹]

-Result

pOH = 9

2.- Calculate the pH

Formula

pH + pOH = 14

-Solve for pH

pH = 14 - pOH

pH = 14 - 9

pH = 5

3.- Calculate the [H⁺]

pH = -log[H⁺]

-Substitution

5 = -log [H⁺]

-Simplification

antilog -5 = [H⁺]

-Result

[H⁺] = 1 x 10⁻⁵

4.- The solution is an acid because the pH was lower than 7.

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