The volume of a given container is 6.2 L, with 19.2 moles of a gas. How many miles are there if we increase the volume to 10.0L

n₂ = 31 mol

Explanation:

Given data:

Initial volume of gas = 6.2 L

Initial number of moles of gas = 19.2 mol

Final number of moles = ?

Final volume of gas = 10.0 L

Solution:

Formula:

V₁/n₁  = V₂/n₂

V₁ = Initial volume

n₁  = Initial number of moles

V₂ = Final volume

n₂ = Final number of mole

Now we will put the values.

6.2 L /19.2 mol = 10.0 L / n₂

n₂ =  10.0 L× 19.2 mol  /6.2 L

n₂ = 192 L.mol /6.2 L

n₂ = 31 mol

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2