A 7.0 L sample of methane gas is collected at 50.0°C.
Predict the volume of the sample at 0°C.

V₂ = 5.92 L

Explanation:

Given data:

Initial volume of methane = 7.0 L

Initial temperature = 50.0°C

Final temperature = 0°C

Final volume = ?

Solution:

Initial temperature = 50.0°C (50+273 = 323 K)

Final temperature = 0°C (0+273 = 273 K)

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 7 L × 273 K / 323 k

V₂ = 1911 L.K / 323 K

V₂ = 5.92 L

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .

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