SiO32- + 2SO32-+ H2O2SO42- + Si+ 2OH-In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent. name of the element oxidized: name of the element reduced: formula of the oxidizing agent:formula of the reducing agent:

oxidizing element=S oxidation number is increasing i.e. +4 to +6

Reducing element=Si oxidation number is decreasing i.e. +4 to 0

Oxidizing agent: = which  oxidizes other but reduce itself.

Reducing agent = which reduces other but oxidize itself.

formula of the oxidizing agent=

formula of the reducing agent=

Explanation:

first write the chemical reaction:

and then write the oxidation state of all the elemet both side i.e. product and reactant:

oxidation state of element of reactant side:

Si=+4

O=-2

S=+4

H=+1

oxidation state of element of product side:

Si=0

O=-2

S=+6

H=+1

from the above it is clearly that:

oxidizing element=S oxidation number is increasing i.e. +4 to +6

Reducing element=Si oxidation number is decreasing i.e. +4 to 0

Oxidizing agent: = which  oxidizes other but reduce itself.

Reducing agent = which reduces other but oxidize itself.

formula of the oxidizing agent=

formula of the reducing agent=

b. accuracy of the data matters alot more than its number of digits, organization or amount of detail. quantitative observation is more accepted than the qualitative observation.

what is the question here. i think you messed up.