What is the pressure of 0.60 moles of a gas if its volume is 10.0 liters at 35.0°C

1.52 atm

Explanation:

Given that:

Volume of gas V = 10.0L

Temperature T = 35.0°C

Convert Celsius to Kelvin

(35.0°C + 273 = 308K)

Pressure P = ?

Number of moles = 0.6 moles

Molar gas constant R is a constant with a value of 0.0821 atm L K-1 mol-1

Then, apply ideal gas equation

pV = nRT

p x 10.0L = 0.6 moles x (0.0821 atm L K-1 mol-1 x 308K)

p x 10.0L = 15.17 atm L

p = 15.17 atm L / 10.0L

p = 1.517 atm (round to the nearest hundredth as 1.52 atm)

Thus, the pressure of the gas is 1.52 atm

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