How many grams of h2 will be produced if 175g of HCI are allowed to react completely with sodium

Chemical reaction:

2HCI + Na —> 2NaCl +H2

4.85 grams of H2 will be produced

Explanation:

Step 1: Data given

Mass of HCl = 175 grams

Molar mass of HCl = 36.46 g/mol

Molar mass H2 = 2.02 g/mol

Step 2: The balanced equation

2HCI + Na —> 2NaCl +H2

Step 3: Calculate moles HCl

Moles HCl = mass HCl / molar mass HCl

Moles HCl = 175 grams / 36.46 g/mol

Moles HCl = 4.80 moles

Step 4: Calculate moles H2

For 2 moles HCl we need 1 mol Na to produce 2 moles NaCl and 1 mol H2

For 4.80 moles HCl we'll have 4.80/ 2 = 2.40 moles H2

Step 5: Calculate mass H2

Mass H2 = moles H2 * molar mass H2

Mass H2 = 2.40 moles * 2.02 g/mol

Mass H2 = 4.85 grams

4.85 grams of H2 will be produced

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