Consider this reaction mechanism:
Step 1: Mo(CO)6- Mo(CO) + CÓ
Step 2: Mo(CO)3 + P(CH3)3- Mo(CO) P(CH3)3
What is the balanced equation for the overall reaction?
0 2M0(CO), + P(CH3)3 -> MOCO)5P(CH3)3
0 Mo(CO)6 + P(CH3)3 → Mo(CO) P(CH3)3
•0 Mo(CO). + P(CH3)3 → Mo(CO)P(CH3)3 + co

Calculate the standard enthalpy of formation of liquid methanol, ch3oh(l), using the following information: c(graphite) + o2 latex: \longrightarrow ⟶ co2(g) latex: \delta δ h° = –393.5 kj/mol h2(g) + o2 latex: \longrightarrow ⟶ h2o(l) latex: \delta δ h° = –285.8 kj/mol ch3oh(l) + o2(g) latex: \longrightarrow ⟶ co2(g) + 2h2o(l) latex: \delta δ h° = –726.4 kj/mol