Suppose two chemical reactions are linked together in a way that the O2 produced in the first reaction goes on to react completely with Mg to form MgO in the second reaction. Reaction one: 2 KClO3 → 3 O2 + 2 KCl Reaction two: 2 Mg + O2 → 2 MgO If you start with 4 moles of KClO3, how many moles of MgO could eventually form

Numbe of mole of MgO form=12

Explanation:

First calculate the number of mole of produced from 4 mole of  

Balance the first reaction:

from the above balanced reaction it is clearly that,

by unitry method,

2 mole of produced 3 mole of

1 mole of produced 1.5 mole of

from 4 mole of   mole of produced

hence we have 6 mole of and this total oxygen will react with Mg

Balance the second reaction:

since produced oxygen in first reaction is reacted completely with Mg means Mg is given in excess quantity,

From the second balanced reacion it is clearly that,

1 mole of produced 2 Mole of MgO

hence 6 mole of will produce 12 mole of MgO

Numbe of mole of MgO form=12

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24