Stock solutions of nitric acid have concentration of 16.0 M. What volume of stock solution is needed to prepare 2.00 L of 2.00 M solution of nitric acid by dilution with water?
500 mL
125 mL
250 mL
32.0 mL
62.5 mL

250 mL

Explanation:

These are the variable one has to have in mind:

= 16 M

= 2 M

= 2 L = 2000 mL

Note: C = concentration; V = volume; subscript 1 = stock solution; subscript = 2 = dilution.

What we have to solve is for

Use the following equation:

x = x ⇒ = ⇒   = 250 mL

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nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.