5. A study of the system, 4 NH3(g) + 7 O2(g) 2 N2O4(g) + 6 H2O(g), was carried out. A system was prepared with [NH3] = [O2] = 3.60 M as the only components initially. At equilibrium, [N2O4] is 0.60 M. Calculate the value of the equilibrium constant, Kc, for the reaction.

The value of the equilibrium constant, Kc, for the reaction is 0.013

Explanation:

Initial concentration of = 3.60 M

Initial concentration of = 3.60 M

The given balanced equilibrium reaction is,

Initial conc.       3.60 M        3.60 M              0 M        0 M

At eqm. conc.     (3.60-4x) M   (3.60-7x) M   (2x) M      (6x) M

The expression for equilibrium constant for this reaction will be,

2x = 0.60 M

x= 0.30 M

Now put all the given values in this expression, we get :

linda: 3 ; laura: 15

step-by-step explanation:

note that linda + laura's age is 18, and that linda is 12 years younger than her sister.

let "linda" = x , "laura" = y:

x + y = 18

x = y - 12

first, plug in y - 12 for x in the first equation:

(y - 12) + y = 18

simplify.

2y - 12 = 18

isolate the variable (y). note the equal sign, what you do to one side, you do to the other. do the opposite of pemdas. first add, then divide.

2y - 12 (+12) = 18 (+12)

2y = 18 + 12

2y = 30

(2y)/2 = (30)/2

y = 30/2

y = 15

next, plug in 15 for y in the second equation (the other equation would work too).

x = y - 12

x = (15) - 12

x = 3

linda's age is 3, laura's age is 15.

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