Calculate the work done in joules when 1.0 mole of water vaporizes at 1.0 atm and 100°C. Assume that the volume of liquid water is negligible compared with that of steam at 100°C and ideal gas behavior.

The amount of work done W = - 30.6 J

Explanation:

Pressure = 1 atm

n = 1 mole

T = 100 °c = 373 K

From ideal gas equation

P V = n R T

Put all the values in above equation we get

1 × V = 1 × 0.08206 ×373

V = 30.6 L

Work done is calculated by

W = - P ΔV

W = - 1 × 30.6

W = - 30.6 J

Therefore the amount of work done W = - 30.6 J

The amount of work done W = -3102 J

Explanation:

Pressure = 1 atm

n = 1 mole

T = 100 °c = 373 K

From ideal gas equation

P V = n R T

Put all the values in above equation we get

1 × V = 1 × 0.08206 ×373

V = 30.6 L

Work done is calculated by

W = - P ΔV

W = - 1 atm × 30.6 L

W = - 30.6 atm.L  = -3102 J

Therefore the amount of work done W = -3102 J

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

why is cellular respiration important for homeostasis?

it changes food into energy that the organism can use.

which of the following is most likely to happen if a cell is not able to divide?

the cell will not be replaced when it is damaged.

explanation: