A sample of argon gas, Ar(g). is placed in a 3.80 L container at 320 K. The gas pressure is 0.496 atm.
How many moles of Ar gas are in the container?

Moles of Ar gas in the container is 0.072 mol.

Given:-

Volume of gas = 3.80 L

Temperature of gas = 320 K

Pressure of gas = 0.496 atm

Number of moles of Ar gas = ?

Ideal gas equation:-

.......(1)

Here, P= Pressure, V = volume, and n = number of moles

R = gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Substitute all the values in equation (1) as follows:-

So, the moles of Ar gas in the container are 0.072 moles.

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n = 0.072 mol

Explanation:

Given data:

Volume of gas = 3.80 L

Temperature of gas = 320 K

Pressure of gas = 0.496 atm

Number of moles of Ar gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will put the values.

n = PV/RT

n = 0.496 atm ×3.80 L / 0.0821 atm.L/ mol.K ×  320 K

n = 1.88 /26.27 /mol

n = 0.072 mol

a. hope i'm right

explanation: