What is the de Broglie wavelength of a proton with a velocity of 2.5e6
m/s?

The  deBroglie wavelength of a proton with a velocity of 2.5e6  is  λ=1.654*10^24 m2 kg

Explanation:

We have the formula,

λ = h/mv

λ = h/p   (p=mv)  assume mass be 1

λ = 6.62607004 × 10-34 m2 kg / s

/2.5*1.602176634*10^−19*10^6

λ = 6.62607004 × 10-34 m2 kg / s  / 4.005425

*10^-13

λ=1.654*10^24 m2 kg

The  deBroglie wavelength of a proton with a velocity of 2.5e6  is  λ=1.654*10^24 m2 kg

c- cold periods in earth's history during which glaciers covered much of the surface.

explanation:

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