If 12.4 moles of Cu and 48.2 moles of HNO3 are allowed to react, how many moles of excess reactant will remain if the reaction goes to completion? 3 Cu + 8 HNO3 → 3Cu(NO3)2 + 2NO + 4H2O

Excess reactant amount 15.1 moles

Explanation:

3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO +4 H₂O

Using mole ratio method we find limiting reagent and excess reagent

For,

Since, Cu is limiting reagent and HNO₃ excess reagent

According to reaction,

              3 moles of Cu react with  8 moles of HNO₃

             12.4 moles of Cu react with = 33.06 moles of HNO₃

So remaining amount of excess   HNO₃  = 48.2 - 33.06

                                                                    = 15.1 moles

answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

hope this and sorry i could only come up with one answer!

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.