2. Calculate the number of grams of nitrogen dioxide that are produced from 4 moles of nitric oxide.
2NO(g) + O2(g)  2NO2(g)

mass of nitrogen dioxide = 368g

Explanation:

From the equation:

2 moles of NO = 2 moles of 2 NO2

4 moles of NO = x moles of NO2

x = (2 × 4)/2 = 8/2 = 4 moles of NO2

No. of moles = reacting mass/ molecular weight

Reacting mass = No. of moles × molecular weight

Reacting mass = 4 × 92 = 368g

the correct answer is:

a. formation of precipitation