You have the equations:

2H2O(l)→2H2(g)+O2(g), △H=572 kJ

2N2(g)+3H2(g)→2NH3(g), △H=−138 kJ
2NO2(g)+7H2(g)→2NH3(g)+4H2O(l), △H=−1.18×103 kJ 2NO2(g)→2N2(g)+2O2(g), △H=□

What is the missing △H ?

−1.38×103 kJ
+99.0 kJ
+1.38 × 10³ kJ
−138 kJ

Which of the following is considered a benefit to using wind energy as a source of power

Problem #3 (ch. 1, problem 15)the ideal gas law provides one way to estimate the pressure exerted by a gas on a container. the law isí‘ťí‘ť=푛푛푛푛푛푛푉푉more accurate estimates can be made with the van der waals equationí‘ťí‘ť=푛푛푛푛푛푛푉푉â’푛푛푟푟â’푞푞푛푛2푉푉2where the term nb is a correction for the volume of the molecules and the term an2/v2is a correction for molecular attractions. the values of a and b depend on the type of gas. the gas constant is r, the absolutetemperature is t, the gas volume is v, and the number of moles of gas molecules is indicated by n. if n = 1 mol of an ideal gas were confined to a volume of v = 22.41 l at a temperature of 0â°c (273.2k), it would exert a pressure of 1 atm. in these units, r = 0.0826.for chlorine gas (cl2), a = 6.49 and b = 0.0562. compare the pressure estimates given by the ideal gas law and the van der waals equation for 1 mol of cl2 in 22.41 l at 273.2 k. what is the main cause of the difference in the two pressure estimates, the molecular volume or the molecular attractions?

Can someone me with questions 12 and 13 plz.