Ina solution prepared by dissolving .100 mole of pro panic acid in enough water to make 1L of solution, the ph is observed to be 2.924. The Ka for propanoic acid (HC3H5O2) is

The Ka for propanoic acid (HC3H5O2) is 2.1 x 10⁻⁵

Explanation:

Concentration of propanoic acid C = moles / volume in Litres = 0.1 mol / 1 L  = 0.1 M

C = 0.1 M

pH = - log [H+]

For weak acids,

[H+] =

pH = - log ()

=  

Ka.C = ()²

Ka = ()² / C

     = ()² / 0.1

      = 2.1 x 10⁻⁵

Therefore,

Ka of propanoic acid = 2.1 x 10⁻⁵

i'm pretty sure its b i might be wrong though!

answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

hope this and sorry i could only come up with one answer!