If 24.2 g of hydrogen react with excess oxygen and 198 g of water are produced what is the percent yield? *
Your answer

The percent yield of the reaction is 90.9%.

Explanation:

Mass of hydrogen gas = 24.2 g

Moles of hydrogen =

According to reaction, 2 moles of hydrogen gas gives 2 moles of water , then 12.1  moles of hydrogen will give:

 water

Mass of 12.1 moles of water

= 12.1 mol × 18 g/mol = 217.8 g

Theoretical yield of water = 217.8 g

Experimental yield of water = 198 g

The percentage yield of reaction:

The percent yield of the reaction is 90.9%.

50.23 i believe is correct but don't quote me on that.