Convert grams of FeCl2 to moles. Then rearrange M = n/V to solve for V: V = n/M (in Liters) What volume of a 0.88 M solution can be made using 130 grams of FeCl2?

1.16L can be made

Explanation:

Molarity = Mol / Volume

Volume = Mol / Molarity

Let's determine the moles of salt, with that mass:

130 g FeCl₂ . 1mol / 126.75 g = 1.02 moles of FeCl₂

Volume = 1.02 mol / 0.88 mol/L → 1.16L