Calculate the Molarity of 89.94 g NaCl is dissolved in 1249 mL of solution.

The molarity of the solution is 1, 23 M.

Explanation:

We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)

Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g

58, 5 g1 mol NaCl

89,94 g x= (89,94 g x 1 mol NaCl)/58, 5 g= 1,54 mol NaCl

1249 ml solution 1,54 mol NaCl

1000ml solutionx= (1000ml solutionx 1,54 mol NaCl)/1249 ml solution

x=1,23 mol NaCl---> The solution is 1, 23 molar (1,23 M)

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.