Describe how you could use IR spectroscopy to distinguish between ethyl acetate and butyric acid. The IR spectrum of butyric acid should have a broad signal between 1650 cm-1 and 1850 cm-1. An IR spectrum of ethyl acetate will not have this signal. The IR spectrum of butyric acid should have a broad signal between 2500 cm-1 and 3600 cm-1. An IR spectrum of ethyl acetate will not have this signal. The IR spectrum of ethyl acetate should have a broad signal between 2500 cm-1 and 3600 cm-1. An IR spectrum of butyric acid will not have this signal. The IR spectrum of ethyl acetate should have a broad signal between 1650 cm-1 and 1850 cm-1. An IR spectrum of butyric acid will not have this signal.

The IR spectrum of butyric acid should have a broad signal between 2500 cm⁻¹ and 3600 cm⁻¹. An IR spectrum of ethyl acetate will not have this signal.

Explanation:

IR spectroscopy is a widely used technique in chemical identifications. In a IR spectrum, signals depend of nature of bonds in the chemical structure of the compound.

Ethyl acetate is an esther. Its principal signal is between 16500cm⁻¹ and 1850cm⁻¹ (Carboxylic compound).

Butyric acid is a carboxylic acid. Carboxylic acids have 2 principal signals: The first is between 16500cm⁻¹ and 1850cm⁻¹ (Carboxylic compound) and the second is between 2500cm⁻¹ and 3600cm⁻¹ (Due the hydrogen bonding between O-H atoms).

Thus, right answer is:

The IR spectrum of butyric acid should have a broad signal between 2500 cm⁻¹ and 3600 cm⁻¹. An IR spectrum of ethyl acetate will not have this signal.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j