1. At what temperature would 3.67 mole P2O3 gas occupy 67.5 L if the pressure is 115
kPa?

The answer for the following question is explained below.

Explanation:

Given:

no of moles (n) = 3.67 moles

volume of the gas (V) = 67.5 liters

pressure of the gas (P) = 115 k Pa

To solve:

Temperature of the gas (T)

We know;

P × V = n × R × T

Where;

P is pressure of the gas

V is the volume of the gas

n is the no of the moles

R is the universal gas constant

here the value of R(universal gas constant ) is 8.314 k Pa./mole.K

We know;

115 × 67.5 = 3.67 × 8.3145 × T

T =  

T =

T = 254.39 K

Therefore the temperature that is require to fill the gas is 254.3 K

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