What mass of H2SO4 would be required to react with 0.75 mil NaOH

36.75 grams of sulfuric acid will be required.

Explanation:

Moles of sodium hydroxide = 0.75 mol

According to reaction, 2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid ,then 0.75 moles of NaOH will :

sulfuric acid

Mass of 0.375 moles of sulfuric acid:

0.375 mol × 98 g/mol = 36.75 g

36.75 grams of sulfuric acid will be required.

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