How many grams are there in 9.03x10^23 molecules of CO2?

66g

Explanation:

A background knowledge of Avogadro's hypothesis proved that 1mole of any substance contains 6.02x10^23 molecules.

From the above findings, we discovered that 1 mole of CO2 also contains 6.02x10^23 molecules.

1 mole of CO2 = 12 + (2x16) = 12 + 32 = 44g

Now we can obtain the mass of CO2 that contains 9.03x10^23 molecules as follow:

44g of CO2 contains 6.02x10^23 molecules.

Therefore, Xg of CO2 will contain 9.03x10^23 molecules i.e

Xg of CO2 = (44x9.03x10^23)/6.02x10^23 = 66g

Therefore, 66g of CO2 contains 9.03x10^23 molecules

the answer is b. dilution