At what temperature in K will 4.00 moles of gas occupy a volume of 12.0 L at a pressure of 5.60 atm?

Considering the ideal gas law, at 204.878 K will 4.00 moles of gas occupy a volume of 12.0 L at a pressure of 5.60 atm.

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances. The numerical value of R will depend on the units in which the other properties are worked.

In this case, you know:

Replacing in the ideal gas law:

5.60 atm×12  L = 4 moles×0.082×T

Solving:

T=204.878 K

Finally, at 204.878 K will 4.00 moles of gas occupy a volume of 12.0 L at a pressure of 5.60 atm.

Learn more about the ideal gas law:

The answer to your question is  T = 204.9°K

Explanation:

Data

Temperature = T = ?

number of moles = n = 4

Volume = V = 12 L

Pressure = P = 5.60 atm

constant of gases = 0.082 atm L /mol °K

Process

To solve this problem, use the Ideal Gas Law and solve it for T

Formula

            PV = nRT

            T = PV / nR

-Substitution

             T = (5.60)(12)/(4)((0.082)

-Simplification

              T = 67.2 / 0.328

-Result

               T = 204.9°K

definition

                    entropy is a measure of the randomness or the extent of disorder of a chemical process.

                      enthalpy is a measure of the heat change of a reaction occurring at a constant pressure.

measurement units:

                        entropy is measured in joule per kelvin (jk⁻¹)   whereas enthalpy is measured in joule per mole (jmol⁻¹)

requirements:

                            entropy has no requirements or limits, and its change is measured by the division between the heat change of the chemical process and the temperature.

                              in contrast, enthalpy can only be related to the heat change of the reaction under standard conditions.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2