Sodium chloride (NaCl) is the chemical name for table salt and potassium chloride (KCl) is a common salt substitute. Using the periodic table, choose the correct statement about how these compounds form. A. Both sodium and potassium atoms gain electrons to form ions. B. Sodium and potassium lose electrons and chlorine gains them. C. Chlorine gains electrons from potassium and loses electrons to sodium. D. Chlorine gains more electrons from potassium than it does from sodium.

Option B. Sodium and potassium lose electrons and chlorine gains them

Explanation:

Sodium and Potassium are both group 1 element. They both react with chlorine by losing 1 electron each and the chlorine atom accept the electron.

Sodium chloride(NaCl) can be formed by the equation below:

Na —> Na+ + e-

Cl + e- —> Cl-

Combining both equation together we obtained the following:

Na + Cl + e- —> Na+ + Cl- + e-

Eliminating the e-, we have:

Na + Cl —> Na+Cl-

From the above illustration, we can see that sodium loses electron and chlorine accepts/gain the electron

This is also applicable to potassium chloride as shown below:

K —> K+ + e-

Cl + e- —> Cl-

Combining both equation together we obtained the following:

K + Cl + e- —> K+ + Cl- + e-

Eliminating the e-, we have:

K + Cl —> K+Cl-

we can see also that potassium loses electron and chlorine accepts/gain the electron

Therefore, the correct answer to the question is option B

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%