For the following reaction, 4.57 g of silver nitrate are mixed with excess copper. The reaction yields 2.29 gram of copper(II) nitrate What is the percent yield for this reaction?Formula: % yield = (Actual yield/theoretical yield) x 100 2 AgNO3(aq) + Cu(s) à Cu(NO3)2 (aq) + 2 Ag(s)

Explanation:

Hello,

In this case, for the given chemical reaction:

If 4.57 grams of silver nitrate are used in copper excess, the theoretical yield of copper (II) nitrate turns out:

In such a way, the percent yield results:

Best regards.

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