How many grams of oxygen are needed to complete the combustion reaction of 4.80 moles of pentane (C5H12)?

1228.8 g of O₂ are needed in the reaction

Explanation:

Combustions reactions make CO₂ and H₂O as products. Let's make the reaciton:

C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O

Oxygen is always one of the reactants

You have 4.80 moles of pentane. Let's make the rule of three (ratio is 1:8)

1 moles of pentane needs 8 moles of oxygen to react

Therefore 4.80 moles will react with (4.80 . 8) /1 = 38.4 moles

We convert the moles to mass: 38.4 mol . 32 g / 1mol = 1228.8 g of O₂

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