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Chemistry, 30.03.2020 17:37 laylah255

E. coli is cultivated in continuous culture under aerobic conditions with a glucose limitation. When the system is operated at D = 0.2 h-1, determine the effluent glucose (S) and biomass concentrations (X) by using the following equations (S0 = 5 g/L):a) Monod equation: νœ‡νœ‡ν‘šν‘šν‘šν‘šν‘šν‘š= 0.25 h-1, Ks = 100 mg/L, ν‘Œν‘Œν‘‹ν‘‹/푆푆푀푀 = 0.4 g X/g S;b) Contois equation: νœ‡νœ‡ν‘šν‘šν‘šν‘šν‘šν‘š= 0.25 h-1, νΎνΎν‘ ν‘ ν‘šν‘š = 0.04, ν‘Œν‘Œν‘‹ν‘‹/푆푆푀푀= 0.4 g X/g SCompare and comment on the results. Why might they be different? [Hint: consider the different assumptions under which each equation operates]

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