The percent ionization of benzoic acid, 2.05 %, at a particular concentration is 25 °C. What was the concentration of benzoic acid in this solution? Ka of benzoic acid is 6.3 × 10-5

Answer : The concentration of benzoic acid in this solution was, 0.149 M

Explanation :

The balanced equilibrium reaction will be,

initially conc.             c                     0                0

At eqm.                    c(1-α)                cα              cα

The expression for dissociation constant is:

when α is very very small the, the expression will be,

Given:

α = 2.05 % = 0.0205

Now put all the given values in this expression, we get:

c = 0.149 M

Therefore, the concentration of benzoic acid in this solution was, 0.149 M

is has three carbons, so the answer is propylamine.

meth-

eth-

prop-

but-

pent-

hex-

hept-

oct-

non-

explanation:

the answer is 303.15 or 303