At a certain temperature the rate of this reaction is second order in SO3 with a rate constant of 1.18·M-1s-1 :2SO3(g)--> +2SO2(g) + O2(g)Suppose a vessel contains SO3 at a concentration of 1.33M .

Calculate the concentration of SO3 in the vessel 8.50 seconds later.

You may assume no other reaction is important. Round your answer to 2 significant digits.

Explanation:

For second order reaction

dC / dt =  -k C²

dC /C² = - kdt

Integrating on both sides,  

[- 1/C  ] = - kt + P , P is a constant .

When t =0 , C = 1.33 M

P =  - 1 / 1.33

[- 1/C  ] =- -  kt -  1 / 1.33

When t = 8.5

[- 1/C  ] =  -  kt - 1 / 1.33

= - 1.18 x 8.5 - 1 / 1.33

= - 10.03 - .7519

= - 10.782

C = .0927 M

= .093 M

that's just how they are

explanation:

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