Use the following equation to calculate the number of moles of Ag that are formed from 3.54 g of Cu completely reacting with excess AgNO3. Use the table of molar masses below.
Cu + 2 AgNO3 --> Cu(NO3)2 + 2 Ag
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0.12 moles of Ag are produced.

Explanation:

Given data:

Mass of Cu = 3.54 g

Moles of Ag produced = ?

Solution:

Chemical equation:

Cu + 2 AgNO₃   →  Cu(NO₃)₂ + 2Ag

Number of moles of Cu:

Number of moles = mass /molar mass

Number of moles = 3.54 g/ 63.55 g/mol

Number of moles = 0.06 mol

Now we will compare the moles of Cu with Ag.

                   Cu         :          Ag

                    1           :           2

                    0.06   :      2×0.06 = 0.12 mol

they are both synthetic elements

explanation:

d