Chemistry, 27.03.2020 19:26 amelvin41

Which of the following will occur when a solution of Pb(NO3)2(aq) is mixed with a solution of KI(aq)?

A.) A precipitate of KNO3 will form; Pb2+ and I– are spectator ions.
B.) A precipitate of Pb(NO3)2 will form; K+ and I– are spectator ions.
C.) A precipitate of PbI2 will form; Pb2+ and I– are spectator ions.
D.) A precipitate of PbI2 will form; K+ and NO3– are spectator ions.
E.) No precipitate will form.

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Answer from: brebob3339

What will happen when Pb(NO3)2(aq) is mixed with a solution of KI(aq) is;

Option D; A precipitate of PbI2 will form; K+ and NO3– are spectator ions.

We want to find what will happen when Pb(NO3)2(aq) is mixed with a solution of KI(aq)

Let us write a balanced equation of this reaction.

Pb(NO3) 2 (aq) + 2KI(aq) = PbI2(s) + 2KNO3(aq)

To answer this question properly, we need to write an ionic equation of the balanced equation above.

Let us first list all the ions present which are;

Pb2+(aq) + 2NO3-(aq) and K+(aq) + I-(aq)

Writing the ionic equation now gives us;

Pb2+(aq) + 2NO3-(aq) + K+(aq) + I-(aq) = PbI2(s) + 2K+(aq) + 2NO3-(aq)

In this ionic equation, we see that it formed PbI2(s) which is a precipitate.

Now, the ions 2K+(aq) + 2NO3-(aq) are on the same side and as such are not participating in the reaction. Thus, they can be called spectator ions.

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Which of the following will occur when a solution of Pb(NO3)2(aq) is mixed with a solution of KI(aq)...

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