The following mechanism has been proposed for the gas-phase reaction of chloroform (CHCl3) and chlorine. Cl2 ⇌ 2Cl (fast, reversible) Cl + CHCl3 → HCl + CCl3 (slow) Cl + CCl3 → CCl4 (fast) What rate law does this mechanism predict? (Choose from the list below and enter your answers in alphabetical order, e. g. ABC ).

Explanation:

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The following mechanism has been proposed for the gas-phase reaction of chloroform (CHCl3) and chlorine.Cl2 ⇌ 2Cl (fast, reversible) Cl + CHCl3 → HCl + CCl3 (slow) Cl + CCl3 → CCl4 (fast) What rate law does this mechanism predict?A)kG) [CHCl3]1/2M) [CCl3]2B) [Cl2]H) [CCl3]1/2N) [HCl]2C) [Cl]I) [HCl]1/2O) [Cl2]2D) [CHCl3]J) [Cl2]1/2P) [Cl]2E) [CCl3]K) [Cl]1/2 F) [HCl]L) [CHCl3]2

The following mechanism has been proposed for the gas-phase reaction of chloroform (CHCl3) and chlorine.Cl2 ⇌ 2Cl (fast, reversible) Cl + CHCl3 → HCl + CCl3 (slow) Cl + CCl3 → CCl4 (fast) What rate law does this mechanism predict?A)kG) [CHCl3]1/2M) [CCl3]2B) [Cl2]H) [CCl3]1/2N) [HCl]2C) [Cl]I) [HCl]1/2O) [Cl2]2D) [CHCl3]J) [Cl2]1/2P) [Cl]2E) [CCl3]K) [Cl]1/2 F) [HCl]L) [CHCl3]2

Question

Asked Oct 30, 2019

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The following mechanism has been proposed for the gas-phase reaction of chloroform (CHCl3) and chlorine.

Cl2 ⇌ 2Cl (fast, reversible)

Cl + CHCl3 → HCl + CCl3 (slow)

Cl + CCl3 → CCl4 (fast)

What rate law does this mechanism predict?

A)kG) [CHCl3]1/2M) [CCl3]2

B) [Cl2]H) [CCl3]1/2N) [HCl]2

C) [Cl]I) [HCl]1/2O) [Cl2]2

D) [CHCl3]J) [Cl2]1/2P) [Cl]2

E) [CCl3]K) [Cl]1/2

F) [HCl]L) [CHCl3]2

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Expert Answer

Step 1

The three step mechanism of the given reaction is,

CL2 dissociate to give chorine a fast and reverse reaction.

React with CHCL3 to give HCL and CCL3 a slow reaction

React with CL to give CCL4.

Step 2

Add equation (1), (2), and (3) to get the overall reaction.

The overall reaction is expressed as,

CL2 dissociate to give chorine a fast and reverse reaction.

React with CHCL3 to give HCL and CCL3 a slow reaction

React with CL to give CCL4.

Step 3

The chlorine atom produced in equation (1) is consumed in equation (3) and CCl3 a molecule is produced in equation (2) is consumed in equation (3).

CL react with CHCL3 to give a reversible reaction of HCL and CCL4.