Potassium chlorate decomposes according to the following chemical equation:
2KCIO3 -- 2KCI + 3O2
If you start with 458g of KCIO3 , what mass (g) of O2 will be produced?
83.71 L O2
179.39 L O2
687 L O2
67.2 L O2

179.4 g of oyxgen will be produced.

Option 2.

Be careful because the units says L instead of g

Explanation:

Decomposition reaction:

2KClO₃ → 2KCl + 3O₂

2 moles of chlorate can decompose to 2 moles of chloride and 3 moles of oxygen.

We convert the mass to moles, and then we make the rule of three:

458 g / 122.55 g/mol =3.74 moles of chlorate

2 moles of chlorate can produce 3 moles of oxygen

Then, 3.74 moles of chlorate may produce (3.74 .3) / 2 = 5.60 moles of O₂

We convert the moles to mass → 5.60 mol . 32 g / 1mol = 179.4 g

179.39 grams of O2 will be produced (option 2 is correct)

Explanation:

Step 1: Data given

Mass of KClO3 = 458 grams

Molar mass KClO3 = 122.55 g/mol

Molar mass O2 = 32.0 g/mol

Step 2: The balanced equation

2KCIO3 → 2KCI + 3O2

Step 3: Calculate moles KClO3

Moles KClO3 = mass KClO3 / molar mass KClO3

Moles KClO3 = 458 grams / 122.55 g/mol

Moles KClO3 = 3.74 moles

Step 4: Calculate moles of O2

For 2 moles KClO3 we'll have 2 moles KCl and 3 moles O2

For 3.74 moles we'll have 3/2 * 3.74 = 5.606 moles

Step 5: Calculate mass O2

Mass O2 = 5.606 moles * 32.0 g/mol

Mass O2 = 179.39 grams

179.39 grams of O2 will be produced (option 2 is correct)

h let me think

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.