What is the percent yield of nacl if 31.0 g of cucl2 reacts with excess nano3 to produce 21.2 g of nacl?

Number of moles  CuCl₂ :

mass solute / molar mass

31.0 / 134.4520  => 0.230 moles of CuCl₂

Mole ratio :

CuCl₂ + 2 NaNO₃ = 2 NaCl + Cu(NO₃)₂ 

1 mole CuCl₂ 2 moles NaCl
 0.230 moles  ? moles NaCl

moles NaCl = 0.230 x 2 / 1

moles NaCl = 0.46 / 1

= 0.46  moles of NaCl ( molar mass 58.44 g/mol )

Mass of NaCl:

1 mole 58.44 g
0.46 moles ( mass of NaCl in theory )

mass of NaCl = 0.46 x 58.44 / 1

mass of NaCl = 26.8824 / 1

= 26.8824 g of NaCl

yield of NaCl :

NaCl produce / NaCl in theory  x 100 %

( 21.2 / 26.8824 ) x 100 

( 0.788 ) x 100 => 78.8 %

hope this helps!

A1 a 2 a 3 ooh lol i think that's it

Vander waals forces are inter molecular bonds that exist within molecules of the same substance. a water molecule is made up of oxygen and hydrogen atoms which share electrons between each other. the vander waals forces are forces that exist between multitude of different  molecules of water. dipole dipole forces is the type of vander waals force that exist in water. the oxygen atom which is more electronegative pulls the shared electron closer to itself thus generating a partial negative charge while the hydrogen acquire a partial positive charge. these two different charges causes attraction to occur in water molecules.