Clutch Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 19.2 g of ethane is mixed with 35. g of oxygen. Calculate the minimum mass of ethane that could be left over by the chemical reaction. Round your answer to significant digits.

9.9 grams

Explanation:-

To calculate the moles, we use the equation:

a) moles of ethane

b) moles of oxygen

According to stoichiometry :

7 moles of oxygen require 2 moles of ethane

Thus 1.09 moles of oxygen require =  of ethane

Thus is the limiting reagent as it limits the formation of product. Ethane is the excess reagent.

Ethane left = (0.64-0.31) = 0.33 moles

Mass of

Thus 9.9 grams of ethane that could be left over by the chemical reaction