What is the empirical formula of a compound that contains 40 percent carbon, 6.7 percent hydrogen, and 53.3 percent oxygen

40g C 6.7g H 53.3g O 100g total Divide each element by its molar mass 40g C x 1mol / 12.01g = 3.33mol C 6.7g H x 1mol / 1.01g = 6.09mol H 53.3g O x 1mol/ 16.00g = 3.33mol O Divide each mole number by the smallest # of moles. In this case, 3.33 is the smallest. 3.33mol C / 3.33mol = 1 C 6.09mol H / 3.33mol = 1.83 H 3.33mol O / 3.33mol = 1 O Empirical Formula = CH2O

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