A solution is prepared using 0.125 g of glucose, , in enough water to make 250. G of total solution. The concentration of this solution, expressed in parts per million, is A) 5.00 x 101 ppm B) 5.00 x 102 ppm C) 5.00 x 103 ppm D) 5.00 x 104 ppm

Option B. 5×10² ppm

Explanation:

In order to determine the concentration of solution at ppm, we should know that ppm indicates mg of solute in 1kg of solution.

We convert the mass of solute from g to mg

0.125 g . 1000 mg / 1g = 125 mg

We convert the mass of solution from g to kg

250 g . 1 kg/ 1000 g = 0.250 kg

ppm = 125 mg / 0.250 kg = 500 ppm

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.