When 943 J of heat is added to 10 grams of oil at 28˚C , the temperature increases to 89˚C. What is the specific heat of the oil?

PLZZZ HELP

1.55 Jg°C

Explanation:

The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = 943 joules

Mass of oil = 10g

C = ? (let unknown value be Z)

Φ = (Final temperature - Initial temperature)

= 89°C - 28°C = 61°C

Then, Q = MCΦ

943 J = 10g x Z x 61°C

943J = 610g°C x Z

Z = (943J / 610g°C)

Z = 1.55 Jg°C

Thus, the specific heat of the oil is 1.55 Jg°C

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