How many milliliters of 2.15 wt% dimethylglyoxime solution should be used to provide a 50.0% excess for Reac- tion 7-2 with 0.998 4 g of steel containing 2.07 wt% Ni

This is an incomplete question, here is a complete question.

How many milliliters of 2.15 wt% dimethylglyoxime solution should be used to provide a 50.0% excess for Reaction 7-2 with 0.998 4 g of steel containing 2.07 wt% Ni?  Assume that the density of the dimethylglyoxime solution is 0.790 g/mL.

Answer : The volume of solution is, 7.195 mL

Explanation :

First we have to calculate the mass of Ni.

Mass of Ni =

Now we have to calculate the moles of Ni.

Now we have to calculate the moles of dimethylglyoxime.

As we know that 1 mole of Ni requires 2 moles of dimethylglyoxime.

So, 0.0003509 mole of  Ni requires (0.0003509×2=0.0007018) moles of dimethylglyoxime.

For 50% excess reaction number of moles of dimethylglyoxime = 0.0007018 × 1.5 = 0.0010527 g

Now we have to calculate the mass of dimethylglyoxime.

Molar mass of dimethylglyoxime = 116.12 g/mole

Now we have to calculate the weight of solution.

As, 2.15 g of dimethylglyoxime present in 100 g of solution

So, 0.1222 g of dimethylglyoxime present in of solution

Now we have to calculate the volume of solution.

Volume of solution = 7.195 mL

Therefore, the volume of solution is, 7.195 mL

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.