The heat released by one mole of sugar from a bomb calorimeter experiment is 5648 kJ/mol. The balanced chemical reaction equation is C12H22O11(s) + 12 O2(g) = 12 CO2(g) + 11 H2O(l) Calculate the enthalpy of combustion per mole of sugar. (answer in kJ/mol) A) 342.3 kJ/mol Eliminate B) 2824 kJ/mol C) 5648 kJ/mol D) 7250 kJ/mol

The answer to your question is the letter C) 5648 kJ/mol

Explanation:

Data

                C₁₂H₂₂O₁₁  +  12 O₂  ⇒   12 CO₂  +  11 H₂O

H° C₁₂H₂₂O₁₁ = -2221.8 kJ/mol

H° O₂ = 0 kJ / mol

H° CO₂ = -393.5 kJ/mol

H° H₂O = -285.8 kJ/mol

Formula

ΔH° = ∑H° products - ∑H° reactants

Substitution

ΔH° = 12(-393.5) + 11(-285.8) - (-2221.8) - (0)

ΔH° = -4722 - 3143.8 + 2221.8

Result

ΔH° = -5644 kJ/mol

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )

answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

hope this and sorry i could only come up with one answer!