Aluminum hydroxide will react with sulfuric acid to produce aluminum sulfate and water. If 0.875 g of aluminum hydroxide reacts exactly with 22.00 mL of a sulfuric acid solution, what is the molarity of the sulfuric acid solution

Molarity of sulphuric acid solution = 0.76 (M)

Explanation:

At first we calculate moles of reacted aluminium hydroxide =

                                                                                                   =

                                                                                                   = 0.011

                  2 Al(OH)₃ + 3 H₂SO₄  →  Al₂(SO₄)₃ + 6 H₂O

Since 2 mole react with 3 mole H₂SO₄

  0.011 mole react with = x 0.011

                                      = 0.016 mole

Molarity of  H₂SO₄  = = = 0.76 (M)

thats how its supposed to be