What is the theoretical mass of water produced from 10 moles of NaHCO3? NaHCO3 + CO2 + H2O

90g

Explanation:

Let us write a balanced equation for the reaction. NaHCO3 decompose to yield water as illustrated below:

2NaHCO3—> Na2CO3 + CO2 + H2O

Theoretical yield of water can be obtained as follow:

From the equation,

2 moles of NaHCO3 produced 1 mole of H2O.

Therefore, 10 mole of NaHCO3 will produce = 10/2 = 5 moles of H2O.

Now we shall convert 10 moles of H2O to grams to obtain the theoretical yield of water. This is illustrated below:

Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

Number of mole of H2O = 5 moles

Mass of H2O =?

Mass = number of mole x molar Mass

Mass of H2O = 5 x 18

Mass of H2O = 90g.

Therefore, the theoretical yield of water is 90g

3

explanation:

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.