Coal gasification can be represented by the equation: 2 C(s) + 2 H2O(g) ĻCH4(g) + CO2(g) ǼH = ? Use the following information to find ǼH for the reaction above. CO(g) + H2(g) ĻC(s) + H2O(g) ǼH = -131 kJ CO (g) + H2O(g) ĻCO2(g) + H2(g) ǼH = -41 kJ CO(g) + 3 H2(g) ĻCH4(g) + H2O(g) ǼH = -206 kJ

The answer is nitrogen-containing bases

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.