At equilibirium,1.0 liter vessel was found to contain 0.2moles,0.2moles B,0.4 moles C, and 0.4 moles D.İf 0.1 moles A and 0.1moles B added to system what will be the new equilibirium concentration of A?
A+B=C+D
reversable reaction

See Explanation and Attachments => New concentration A = 0.10 mol/L

Explanation:

Explanation:

              A         +        B         ⇄        C       +        D

C(i):   0.20 mol      0.20 mol         0.4 mol       0.4 mol

ΔC:   -0.10 mol      -0.1 mol          +0.1 mol       +0.1 mol    

C(eq):  0.10 mol      0.10 mol          0.5 mol       0.5 mol

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=> A & B react to form more C & D as reaction shifts right to establish new equilibrium with new concentration values. See attached diagram. => I call this the 'chemical see-saw analysis'.  

=> Also attached is a summary of stress factor effects of temperature and pressure-volume changes.