(b) 1.03 x 10^24 atoms Mn into grams
(c) 3.60 x 10^22 atoms He
into grams
(d) 2.88 x 10^15 atoms N
into grams
(e) 2.88 x 10^15 atoms U into grams

a.  94 g of Mn

b. 0.239 g of He

c. 6.69ₓ10⁻⁸ g of N

d. 1.14ₓ10⁻⁶ g of U

Explanation:

This is the way to make the conversions:

Number of atoms → Moles of element → grams

We begin from the information that: 1 mol of atoms has 6.02×10²³ (NA) atoms

Let's convert all the numbers to amount of moles (number of atoms / NA)

a.  1.03 x 10²⁴ of Mn / 6.02×10²³ = 1.71 moles of Mn

b. 3.60 x 10²² of He / 6.02×10²³ = 0.0598 moles of He

c. 2.88 x 10¹⁵ of N /6.02×10²³ = 4.78ₓ10⁻⁹ moles of N

d. 2.88 x 10¹⁵ of U /6.02×10²³ = 4.78ₓ10⁻⁹ moles of U

We convert the moles to mass (moles . molar mass)

a.  1.71 moles of Mn . 54.94 g /1mol = 94 g of Mn

b. 0.0598 moles of He . 4 g /1mol = 0.239 g of He

c. 4.78ₓ10⁻⁹ moles of N . 14 g /1mol = 6.69ₓ10⁻⁸ g of N

d. 4.78ₓ10⁻⁹ moles of U . 238.03 g /1mol = 1.14ₓ10⁻⁶ g of U

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied

the correct answer would be b. amelia, because the particals of gas move really fast (charged particals) and gas also has a lot of room (particals move independently) so the only answer that has both of those is amelia's.