2. When 400 J of heat is added to 5.6 g of olive oil at 23*C, the temperature increases to 87*C. What is the specific heat of the olive oil? (Show all work including the equation you use to solve). (3 points). See page 561 for an example.

The answer to your question is C = 1.116 J/g°C

Explanation:

Data

Q = 400 J

mass = 5.6 g

Temperature 1 = T1 = 23°C

Temperature 2 = T2 = 87°C

Specific heat = C = ?

Formula

Q = mC(T2 - T1)

- Solve for C

C = Q / m(T2 - T1)

- Substitution

C = 400 / 5.6 (87 - 23)

- Simplification

C = 400 / 5.6(64)

C = 400 / 358.4

- Result

C = 1.116 J/g°C

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