A meteorological balloon contains 250.0 l he at 22°c and 740.0mmhg if the volume of the balloon can vary according to external conditions what volume would it occupy at an altitude at which the temperature is -52°c and the pressure is 0.750 atm

243.15 l

Explanation:

Using the general gas law

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁T₂/P₂T₁ where P₁, V₁ and T₁ are the initial pressure, volume and temperature of the meteorological balloon and  P₂, V₂ and T₂ are the initial pressure, volume and temperature of the meteorological balloon.

P₁ = 740 mmHg V₁ = 250 l and T₁ = 22°C + 273 = 295 K,

P₂ =  0.750 atm = 0.750 × 760 mmHg = 570 mmHg (since 1 atm = 760 mmHg) and T₂ = -52°C + 273 = 221 K  

V₂ = P₁V₁T₂/P₂T₁ = 740 mmHg × 250 l × 221 K/570 mmHg × 295 K = 243.15 l

V₂ = 243.15 l

So the volume it would occupy at an altitude of temperature -52 °C where it pressure is 0.750 atm  is 243.15 l

answer: option (4) is the correct answer.

explanation:

areas which are at low altitudes and near the equator tend to receive direct sunlight from the sun. hence, heat energy or radiations from the sun make these areas warmer and they have warmest water.

whereas areas which are at high altitudes and away from the equator do no receive direct sunlight. hence, no direct contact from the sun makes these regions colder and thus, they have colder water.

thus, we can conclude that the statement areas at low latitudes near the equator have the warmest water because they receive the most direct sunlight best explains the relationship between an area's geography and the temperature of its surface water.

he would use the colour black